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(x)=6x^2-12-90
We move all terms to the left:
(x)-(6x^2-12-90)=0
We get rid of parentheses
-6x^2+x+12+90=0
We add all the numbers together, and all the variables
-6x^2+x+102=0
a = -6; b = 1; c = +102;
Δ = b2-4ac
Δ = 12-4·(-6)·102
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2449}}{2*-6}=\frac{-1-\sqrt{2449}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2449}}{2*-6}=\frac{-1+\sqrt{2449}}{-12} $
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